Question on: JSS3 Mathematics - Variations
If π¦ varies inversely as π₯ and π¦=20 when π₯=4, find π¦ when π₯=5.
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Given π¦=π/π₯, substituting the given values:
20=π/4
Solving for π:
π=20β 4=80
Now, find π¦ when π₯=5:
π¦=80/5=16
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